29 Aug
2001
29 Aug
'01
2:18 p.m.
Roeland, --On Wednesday, 29 August, 2001 10:13 AM -0700 Roeland Meyer <rmeyer@mhsc.com> wrote:
|> Draw two curves, the first y=x/2, the second y=x^2 |> Move the value of x for y=1 for the first curve left by 2, 5 or 10 |> and it will still be surpassed by the second curve. |> You will even see this for a second curve of y=x*2 or y=x.
Prove it.
Prove that y1=A(x^2)+Bx+C always exceeds y0=Dx+E for positive A and D, for all x>x0 for some value x0? Um, y1-y0 = A(x^2) + (B-D)x + (C-E) [1] This is a positive parabola with standard solutions. To the right of it's higher root, it's always positive, so y1>y0. Now, I take it you don't want proof of the roots to quadratic equations? -- Alex Bligh