9 Aug
2021
9 Aug
'21
2:33 p.m.
On Mon, Aug 9, 2021 at 10:31 AM Sabri Berisha <sabri@cluecentral.net> wrote:
Just for fun, I did the math. A total of 16,777,216 /24s fit in 32 bits. Take away all the reserved space as per IANA (this is 1,266,696 /24s, see below), and we end up with 16,777,216 - 1,266,696 = 15,510,520 potential /24 advertisements.
Howdy, It's not that simple. For example, 224/4 is not a 'reserved' space but it can't appear in the unicast BGP table either. That alone is a million routes unaccounted for in your math. Regards, Bill Herrin -- William Herrin bill@herrin.us https://bill.herrin.us/