On Tue, Jun 16, 2009 at 09:23:22PM +0000, Chris Morrow wrote:
On Tue, 16 Jun 2009, Chris Morrow wrote:
On Tue, 16 Jun 2009, Michael Sinatra wrote:
If I have decoded the 6to4 address properly, the RAs are being announced by the host with IPv4 address 75.196.207.17, which is a Verizon Wireless
code to decode addr pls.
i ask because:
morrowc@tweezer:~$ ifconfig wlan0 | grep 2002 inet6 addr: 2002:4bc4:cf11:b:58bd:5bee:d59b:c8c6/64 Scope:Global inet6 addr: 2002:4bc4:cf11:b:21d:e0ff:fe90:1acb/64 Scope:Global inet6 addr: 2002:4bc4:cf11:b:74b9:a96e:55af:6abd/64 Scope:Global inet6 addr: 2002:4bc4:cf11:b:dd31:7550:87c2:747b/64 Scope:Global inet6 addr: 2002:4bc4:cf11:b:91d2:ac70:e21c:157f/64 Scope:Global inet6 addr: 2002:4bc4:cf11:b:a425:3a98:1398:2dbd/64 Scope:Global
it'd be nice to hammer down on the others there :) (other 6 from what I can tell)
Here's my 1-line of python: #!/usr/local/bin/python import sys, socket, struct print socket.inet_ntoa(struct.pack("!I", int(sys.argv[1],16))) Extract the 32 bits (8 hex digits) after 2002: and feed it to this script: $ hex2ip 4bc4cf11 75.196.207.17 --Shumon.
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